Solved Turning args into ints

Hey Guys, I am in a bit of a struggle. I honestly have no idea how to get around it.

Code:

public boolean onCommand(CommandSender sender, Command cmd, String lable, String[] args){
    
        FileConfiguration config = this.getConfig();
        if (cmd.getName().equalsIgnoreCase("et") && sender instanceof Player){
            Player player = (Player) sender;

            int total = config.getInt("tokens." + player.getName().toLowerCase());
            player.sendMessage(ChatColor.GREEN + "You have " + ChatColor.GRAY + total + ChatColor.GREEN + " Tokens");
        return true;
    
        }else if (cmd.getName().equalsIgnoreCase("etgive") && sender instanceof Player){
            Player player = (Player) sender;
            int length = args.length;
            if (length == 1) {
                for (Player playerToGiveToken : Bukkit.getServer().getOnlinePlayers()){
                    if(playerToGiveToken.getName().equalsIgnoreCase(args[0])){
                        playerToGiveToken.getInventory().addItem(new ItemStack(Material.BEDROCK, 1));
                        playerToGiveToken.sendMessage(ChatColor.GOLD + player.getName() + " Has Given You a Token!");
                        player.sendMessage(ChatColor.GOLD + "You have given " + playerToGiveToken.getName() + " A Token!");
                    }
                }
            }    
        
        return true;
    
        }
    return false;
    }

I have highlighted the area where I am having trouble, So Where it gives me bedrock, I want to change the 1 to args[1] but then I cant do that, because I declared args as a String. I have tried

Code:

 Int amount = args[1]; 

But then there is an error, any ideas?
-Edit you cant see the highlighted area, sorry. Problem is on line 18 and 2

 

well that was simple o_o, thanks!

 

@pingpong1999 use a try/catch statement where you parse the string to a int (or whatever) and check for NumberFormatException to catch the error so you can display the player that the value is not valid.