[SOLVED] Check if part of a string is an integer?

So I have String args[] passed into one of my functions but sometimes a certain index in the array will be an integer. What is the best way to check that (for example) args[1] is an integer?

 

Don't know if there's an easier way but this should work:

Code:

Integer myInt = 0; // default value
try {
    myInt = Integer.valueOf(myString);
} catch(NumberFormatException x) {
    // assume it's not a number and do whatever you want
}

 

How can you declare myInt twice? And why?

 

Because I stuffed up My original code has the declaration inside the try/catch but I figured this might not be useful for the request above so I declared myInt outside the try/catch but forgot to remove the first declaration - fixed

 

Is it difference between declaring in or out? Recenty I found that Eclipse compiler moves such expressions out of try{} automatically.

 

When you declare something inside try it is not visible outside. Thats cause the code may not have been executed because of the exception.

And you can also use a regex:

Code:

if(myString.match("\\d+"))
{
//it is an integer
}

 

@avatarDr

Well, my original code was a little different:

Code:

String myConvertedString  = null;
try {
    Integer myInt = Integer.valueOf(myString);
    myConvertedString = myInt.toString();
} catch(NumberFormatException x) {
    // assume it's not a number and do whatever you want
}

Because I later needed to use the number as a string however if the original "myString" was not a number there's a lot of other code that runs. Hence my need to declare it inside - as masteroftime pointed out, if you declare it inside the try/catch then it's not visible outside the try/catch.

 

That is just what I needed. Thank you very much.