Solved Inventory slots math

Hi, basically I have a 54 slots inventory, and I want to make it so if player equals 1 - they can only click on the left half of the inventory - if player equals 2 - they can only click on the right half - else false. No one can click in the middle column of the inventory.

At the moment I have this:

Code:

    public boolean canClick(int player, int itemSlot) {
        return player == 1 ? (itemSlot >= 0 && itemSlot < 4) || (itemSlot >= 9 && itemSlot < 13) || (itemSlot >= 18 && itemSlot < 22) || (itemSlot >= 27 && itemSlot < 31) || (itemSlot >= 36 && itemSlot < 40) || (itemSlot >= 45 && itemSlot < 49) : (player == 2 ? (itemSlot > 4 && itemSlot <= 8) || (itemSlot > 13 && itemSlot <= 17) || (itemSlot > 22 && itemSlot <= 26) || (itemSlot > 31 && itemSlot <= 35) || (itemSlot > 40 && itemSlot <= 44) || (itemSlot > 49 && itemSlot <= 53) : false);
    }

Though - it is one of the most long lines of code I've seen in my life. I'm definitely sure there's a simple Maths operation/formula to automatically do this, but my mind is blank at the moment and I just can't think. Can anyone else help me? :3

Ronbo gave me this:

Code:

itemSlot % 9 < 4 ? left : itemSlot % 9 > 4 ? right : middle

I'll test this.

Edit: I cannot test until the plugin is made but I guess this'll work:

Code:

return player == 1 ? itemSlot % 9 < 4 : (player == 2 ? itemSlot % 9 > 4 : false);

EDIT by Moderator: merged posts, please use the edit button instead of double posting.

 

So you're trying to simplify this?

Shouldn't it be

Code:java

return player == 1 ? itemSlot % 9 < 4 : player == 2 && itemSlot % 9 > 4);

EDIT by Moderator: merged posts, please use the edit button instead of double posting.

 

That's (exactly) what he did, thanks, yeah. That worked :3

 

No problem, but who's "he?"

 

Lactem