input problem.

hello.
i am trying to take over an plugin.
since i am very new in java, I don't know much.
in the plugin you can only auction items by typing their ID.
but i also want to auction items by typing their name.
how would i do that?

Code:

int count = 0;
                    try
                    {
                        id = Items.validate(msg[2]);
                    }

does something with this

this stands in the Items.validate

Code:

public static int[] validate(String item)
    {
        int ret[] = {
            -1, 0
        };
        Material m = null;

        try
        {

            ret[0] = Integer.valueOf(item).intValue();
            m = Material.getMaterial(ret[0]);
        }
        catch(NumberFormatException e)
        {
            m = Material.matchMaterial(item);
            String val = "";
            for(Iterator iterator = iAuction.items.keySet().iterator(); iterator.hasNext();)
            {
                String id = (String)iterator.next();
                if(id.equalsIgnoreCase(item))
                {
                    val = (String)iAuction.items.get(id);

                }
                else
                if(((String)iAuction.items.get(id)).equalsIgnoreCase(item))
                    val = id;
            }

            if(val.contains(","))
            {
                String split[] = val.split(",");
                ret[0] = Integer.valueOf(split[0]).intValue();
                ret[1] = Integer.valueOf(split[1]).intValue();
            } else
            {
                ret[0] = Integer.valueOf(val).intValue();
            }
            if(ret[0] == -1)
                return ret;
        }
        if(!checkID(ret[0]))
        {
            ret[0] = -1;
            return ret;
        } else
        {
            return ret;
        }
    }

 

I'm doing this by heart so bear with me please.

Code:

public static int[] validate(String itemName, int itemID))

then do a if like this

Code:

if(itemName !=null){
//make the material with the name
}
else{
//make the material with the ID
}

 

then another question, how do i get the Material to integer?

 

Im not sure if this is right I dont have an IDE here but:

Code:

m = Material.getMaterial(ret[0]);

using the m i think theres something like m.getValue() or something like that

 

that gives an error: "Cannot convert Material to int".

 

Material.getId()

 

with this i get:
The method getId() in the type Material is not applicable for the arguments (Material)

but it had to be m.getId().
but it still won't work.

EDIT by Moderator: merged posts, please use the edit button instead of double posting.

 

Code:

Material mat = Material.IRON_BLOCK;
System.out.println(mat.getId()+"");

This works

 

So if i do this, it will look if it is an integer or a string?

 

I'm not sure whether I understand you problem.
If you want to get a Material you can use

• Material.getMaterial(intid)
• Material.getMaterial(Stringname)
• Material.matchMaterial(Stringname)

Your if will check whether the string isn't null, which doesn't mean it checks whether it's a number or not.

 

i meant: if "itemName != null" returns true, does that mean it is an integer?

 

Nope,

Code:

String itemName = "hallo";
Sytem.out.println(itemName != null);

will give you true.

Code:

try
{
    int number = Integer.decode(aString);
}
catch(NumberFormatException ex)
{

}

If you don't want to use exceptions I could post a snippet checking if a string is a number.

 

that would be fine, thanks
btw, you're dutch?

 

No, why do you ask, do I have a dutch accent? Though accent may be an inappropriate word when applied to written text.

 

no you said, hallo.
hallo = hello in Holland.
so you have an dutch accent

 

Ahh, it's hallo in German too.

 

and you are German?
anyway, back to the subject.

 

yes

Are there any problems left?

 

i now have it that it ONLY works with the item name.
and not with the id anymore

 

Code?
However shouldn't be that difficult

Code:

Material getMaterial(String name)
{
    Material mat = null;
    try
    {
        mat = Material.getMaterial(Integer.decode(name));
    }
    catch(NumberFormatException ex)
    {
        mat = Material.matchMaterial(name);
    }
    return mat;
}

if the return value of the method is null, there's no such material.

 

Most servers have a file in their main folder, called items.txt. If you just look for the item in there with the Properties, you will get an ID, which you can use

 

Why would he use something other than Material.getId() ?

 

because that eeh.. idk. I'm just sayin

 

i know, because the items.txt doesn't have those stupid: _

 

when i do that, i get the error: cannot convert from material to int[].
what could i do against that?

 

What did you change?

 

here is it:

Code:

public static int[] validate(String item)
    {
        int ret[] = {
            -1, 0
        };
        Material m = null;

        try
        {

            //if(item !=null){
                //m = Material.getMaterial(item.toUpperCase());
                //ret[0] = m.getId();
                //}
                //else{
                //    ret[0] = Integer.valueOf(item);
                //make the material with the ID
                //}
            //below is what i changed
            {

                try
                {
                    m = Material.getMaterial(Integer.decode(item));
                }
                catch(NumberFormatException ex)
                {
                    m = Material.matchMaterial(item);
                }
                return m;
            }
    
        }
        catch(NumberFormatException e)
        {

             String val = "";
            for(Iterator iterator = iAuction.items.keySet().iterator(); iterator.hasNext();)
            {
                String id = (String)iterator.next();
                if(id.equalsIgnoreCase(item))
                {
                    val = (String)iAuction.items.get(id);

                }
                else
                if(((String)iAuction.items.get(id)).equalsIgnoreCase(item))
                    val = id;
            }

            if(val.contains(","))
            {
                String split[] = val.split(",");
                ret[0] = Integer.valueOf(split[0]).intValue();
                ret[1] = Integer.valueOf(split[1]).intValue();
            } else
            {
                ret[0] = Integer.valueOf(val).intValue();
            }
            if(ret[0] == -1)
                return ret;
        }
        if(!checkID(ret[0]))
        {
            ret[0] = -1;
            return ret;
        } else
        {
            return ret;
        }
    }

 

You want to get the item by number in the try.

Code:

 m = Material.getMaterial(Integer.decode(item));

Code:

                else{
                    ret[0] = Integer.valueOf(item);

                }

How would you get the value if item is null?
I don't really get what your code should do.
Edit: posted before your second post

 

i want to get the item by number and by name.

 

Yeah but this Iterator and split string stuff.