If one array equals, generate next random and try again

Basically exactly what the title says

I have an array of numbers, and a random int generator.
If even one array equals the current random number, get another random number and try again, then keep retrying until valid number is found.

I know how to do this with one value, but not with multiple in an array.

Thanks in advance

 

Code:

boolean tryAgain;
int x;
do{
    x = however you get the random number (Math.random(), Random class, etc.)
    tryAgain = false;
    for ( int i = 0; i < myArray.length; i++ ){
          if ( myArray[i] == x ){
              tryAgain = true;
              break;
          }
    }
}while(tryAgain);

x is your random number, myArray is your array. Get the random number first, and set tryAgain to false. Loop through the array, and if the number at a given spot equals the random number, set tryAgain to true and break out of the loop so it will loop again with a new random number. Otherwise exit the loop because no matches were found.

Is this what you were asking?

 

Works like a charm.
And thank you for explaining it too!

 

You're quite welcome!