How to get all of the arguments after args[1] in a command

so right now i use

Code:

String name = args[2];
plugin.setDisplayName(((Player) sender).getItemInHand(), name);

I want the name to be everything after args[1]. how can i do that? it works now,
but it can only be 1 word with no spaces. i want "name" to be all the args after args[1]

 

hello william9518,
you could use this: (i haven't tested it but i should work fine)

PHP:

public String allArgs(int start , String[] args){
    String temp = "";
    for(int i = start ; i < args.length ; i++){
     temp += args[i] + " "; 
    }
   return temp.trim();
}


 

Or you could do this...

Code:java

if(args.length >= 2){
    StringBuilder message = new StringBuilder();
    for(int i = 1; i < args.length; i++){
        message.append(" ").append(args);
    }
    message.toString();
}

It will makes all arguments from args[ 1 ] and onwards into one String.

 

Code:

        StringBuilder sb = new StringBuilder();
        for(int i = 0; i < args.length; i++) {
            if (i > 0) sb.append(" ");
            sb.append(args[i]);
        }

Use sb.toString(); to the if you need to send it to a user. I use the Space part at the top so that way no need to trim it.
Also say you want to start on args[1] just change i = 0; to i = 1;

Edit: I add the if (i > 0) so it doesn't add a space at the start and because its above the argument onces it put the first argument in it will put the space. So you don't get unwanted space at the front or the back then you have to trim it and all that.