Plugin Help How do I check if an arg is an int

Like the title says, How do I check if an arg is an int? I've looked it up and all I could find was this
​

Code:

public static boolean isInt(String string) {
try {
Integer.parseInt(string);
} catch (NumberFormatException nFE) {
return false;
}
return true;
}

Whenever I do this I get an error

Could anyone help?

Thanks!

bump

EDIT by Moderator: merged posts, please use the edit button instead of double posting.

 

It's because it isn't final that you're getting that error

 

@timtower I get an error though

 

@timtower If I click it I get another error (It says the same thing on the other side but with a backwards bracket)

If I click the error I add brackets to the front and back of the first line I get this:

 

The method itself is fine, there's probably something wrong with the code above it, causing it to not be able to parse your method.

 

I'm not having any issues using this.
Try this:

boolean isInt (String s)
{
Integer i = Integer.parseInt(s);
return false;
}
I'm surprised there is no tryParse function for Integer.

 

In your Parameters, the String needs to be final, so it would look like this;

Code:

public static boolean isInt(final String string) {
      try {
      Integer i = Integer.parseInt(string);
      } catch (NumberFormatException e) {
      return false;
     }
     return true;
   }

What this does is that it tries toe parse the int, if it cannot, it will catch the exception and return false, if it succeeds, it will return true

 

No it doesn't.

Your code is the exact same as the OPs except with a syntax error.

 

Ok, fixed the errors, I was doing it fast and did not see the errors, my bad.
Mine is different because I put "Integer i = Integer.parseInt(string);" in my code. Although testing both mine and his, I got no errors either way.

@ObviousEmeralds I have tested both codes in my Development enviroment and have found no errors, I do not get that final error either. Could you send the full code please via pastebin.com?

 

@ObviousEmeralds Using a try catch block to find if a String is an integer is horrible practice. Especially since you're catching a runtime exception (read: http://stackoverflow.com/a/24344547). Apache commons, which is packaged with Bukkit, has a nice little method for this: StringUtils#isNumeric(CharSequence cs). What that's doing behind the scenes is iterating through each character and using Character#isDigit().

 

@Mrs. bwfctower I have never heard of Apache commons, then I looked through the links, and I now Highly suggest it.
@ObviousEmeralds Use the Apache commonons as @Mrs. bwfctower suggested.
https://commons.apache.org/downloads/index.html
I am not sure which one to download though

 

@Jayfeather331 it's packaged with Bukkit