Get all possible branches from yml config.

So let's say the config looks like:

Code:

players:
    herp: 1
    derp: 2
    flerp: 3

Is there a way to get herp, derp and flerp in one list/array?
Thanks in advance

 

I'm not 100% sure but I think this can do it.

 

That is what I want and what I found earlier, except not in the root.
I want to get everyone in "players".

 

Code:java

getConfig().getList("players");

 

Nope.

That's more like a "getString("something")" method.
Thanks anyway

 

Err... no it's not.

Code:java

getConfig().getString("path.to.string");

Would get you:

Code:

path:
  to:
    string: This is what would be returned

Code:java

getConfig().getString("path.to.list");

Would get you:

Code:

path:
  to:
    list:
      - This
      - Would
      - Be
      - Returned

Unless I have misunderstood your question.

 

getKeys(false) will do the job. But, you'll have to grab the section in which herp, derp and flerp are located.

Try this:

Code:

FileConfiguration config = getConfig();

Set<String> players = config.getConfigurationSection("players").getKeys(false);

 

Okay, I'll say exactly what I want to do.

Code:

users:
    derp:
        permissions:
            permissions.example: true
        groups:
        - admin
   herp:
        permissions:
            permissions.example: true
        groups:
        - admin
    flerp:
        permissions:
            permissions.example: true
        groups:
        - admin

That's what the PermissionsBukkit file looks like.
I want to get all the users in the file, nothing more, nothing less.

So as the output here, I want "derp, herp, flerp".
I hope you understand what I mean.

EDIT: Thank you DDoS.
That's exactly what I was looking for.

Previously I was looking for something such as "setRoot("users")" or something.

 

Oh, I did misunderstand, my mistake.

 

Haha, no problem.
Thanks for the effort.