Bukkit getting 2 online players.

Hi there,

I need some help. I am trying to figure out how I can get only 2 online and forget the rest. Taking those 2 players and sending them into an Array. Does anyone know how I can do that? Just fetching 2 players out of all the other online players.

 

What have you tried?

 

Player random = Bukkit.getOnlinePlayers()[new Random().nextInt(Bukkit.getOnlinePlayers().lenght)]
You should be able to figure out the rest

 

@Monkey_Swag What if it gets the same player?

@teej107 Yeah I looked up a couple of topics, tried my own but there is nothing related to and is kinda hard to me.

EDIT by Moderator: merged posts, please use the edit button instead of double posting.

 

It's a simple extra conditional statement

 

@mrgreen33gamer Just check to see if you already have that player selected. If you get the same one again, just try again.

 

That is only if he is using a version where it returns an array.

 

True, forgot CB 1.7.10 changed it to a collection. I personally use 1.7.9

 

If it was up to me, I would just iterate through the online players and increment an integer for each iteration up until the integer is equal to the random number. Adding the online players to a collection may throw an error if you are using the wrong version and same with

It might not be the most efficient but it'll work with 1.7.9 and 1.7.10