SOLVED For anyone that needs to know how to do it (whether they find it via google or what not). right click your batch/bat file (Bukkit Server Launcher), open with notepad++ or whatever editor you have. At the bottom you will see something like: Code: timeout/nobreak 1 >NUL IF /I "%PROCESSOR_ARCHITECTURE:~-2%"=="64" java -d64 -Xincgc -Xmx1560M -jar "%~dp0craftbukkit-0.0.1-snapshot.jar" IF /I "%PROCESSOR_ARCHITECTURE:~-2%"=="86" java -Xincgc -Xmx1024M -jar "%~dp0craftbukkit-0.0.1-snapshot.jar" PAUSE I know I run on x64 (x86 is 32 bit), so I just deleted that command and ended up with the end of the file looking like: Code: timeout/nobreak 1 >NUL IF /I "%PROCESSOR_ARCHITECTURE:~-2%"=="64" java -Xmx2G -Xms2G -jar craftbukkit-0.0.1-snapshot.jar PAUSE -Xmx stands for max and -Xms stands for minimum. I know I always have 2 gigs available (3 if I stop watching netflix), so I go with 2, leaving me with about a gig of RAM to myself. Run it and you should be good to go!
You mean the craftbukkit server launcher? Because anytime I paste that into there it just says [INFO] Unknown console command. Type "help" for help. I am pasting: java -Xmx1G -Xms1G -jar craftbukkit-0.0.1-snapshot.jar (the name of the jar mentioned in the other thread).
Right, it doesn't work. =\ Nevermind figured it out myself. EDIT by Moderator: merged posts, please use the edit button instead of double posting.
here, try this:http://forums.bukkit.org/threads/craftbukkit-auto-installer-beginners.26555/ or if you just want the code: Code: @ECHO OFF title CraftBukkit Server color 17 IF /I "%PROCESSOR_ARCHITECTURE:~-2%"=="64" java -d64 -Xincgc -Xmx1560M -jar "%~dp0craftbukkit-0.0.1-snapshot.jar" IF /I "%PROCESSOR_ARCHITECTURE:~-2%"=="86" java -Xincgc -Xmx1024M -jar "%~dp0craftbukkit-0.0.1-snapshot.jar" PAUSE