Getting Display Name of a shot arrow

Is there any way to get an arrows display name from the ProjectileHitEvent. If not, how would i get if the arrow has a specific name when its shooting?

Thanks for any help.

 

I would guess that you have to work with metadata

 

Yes i have checked but i cant find a way to get the display name. Im thinking that the arrow is just a plain arrow entity and wont have the metadata of the ItemStack i made.

 

hmm what if you check if the damager is a instanceof Arrow? I did this with the DamageByEntityEvent it seems a arrow is a entity aswell then make the type Arrow and cast it to the damager, can you get the displayname from there??

also maybe this is optional regarding what ive read from other posts

Code:

Arrow arrow = (Arrow) e.getDamager().getMetadata("DisplayName");

it seems the list from getMetadata has a entry called DisplayName if I'm correct.

edit I ment EntityDamageByEntityEvent

 

k ill try thanks.

xize
I tried this but it didn't work, not sure if its how you do it.

Code:

@EventHandler
    public void projectileHitEvent(ProjectileHitEvent e){
 
            System.out.println("1");
   
            Arrow arrow = (Arrow) e.getEntity();
 
            if(!(arrow instanceof Arrow)) return;
   
            System.out.println("2");
 
            if(arrow.getMetadata("DisplayName").equals("Explosive Tip Arrow")){
       
                System.out.println("3");
 
                e.getEntity().getWorld().createExplosion(e.getEntity().getLocation(), 1);
            }
    }

Edit: Just for reference here is the ItemStack

Code:

        ItemStack explosiveTipBow = new ItemStack(Material.ARROW, 1);
        meta = explosiveTipBow.getItemMeta();
        meta.setDisplayName("Explosive Tip Arrow");
        explosiveTipBow.setItemMeta(meta);
 
        ShapedRecipe explosiveTipBowRecipe = new ShapedRecipe(explosiveTipBow).shape("*","%"," ").setIngredient('*', Material.SULPHUR).setIngredient('%', Material.ARROW);
 
        getServer().addRecipe(explosiveTipBowRecipe);

EDIT by Moderator: merged posts, please use the edit button instead of double posting.

 

the code seems good though any errors like a npe?
especially on line 7 of the first snippet?

also try a try and catch expression with the meta maybe it shows something

edit what if you change the getMetadata("DisplayName") to getMetadata("DisplayName").toString().equalsIgnorecase("Explosive Tip Arrow");

 

No errors it gets two Message "2" and the does nothing.

 

hmm what you can try is to print out the getMetadata("DisplayName").toString(); to see if it's valid

 

When a player shoots an arrow, I don't think the metadata from the ItemStack is carried over to the Arrow entity. You should add a listener for ProjectileLaunchEvent and give the Arrow the metadata when it is fired.

 

xize
It prints out empty square brackets. "[]"

 

Searching is nice
http://forums.bukkit.org/threads/detecting-when-hit-by-an-arrow-and-from-who.142480/

Edit: That explains it as well Tag the arrows with metadata

 

Arrow entities can't have a DisplayName NBT property. Only mobs can. I'm pretty sure of this, and haven't read the whole thread, so correct me if I'm wrong.

 

So how do i know to tag the correct arrow? If i am correct its in the ProjectileLaunchEvent but how would i compare it to the itemstack there?

 

Heh, good question. You can't get the itemstack there either. So I guess you just need to add a way the player can switch to using his special arrow (using commands or right-clicking with a bow) and check his inventory if he has that special arrow.

 

ok thanks for your help.

 

These two lines:

Code:

Arrow arrow = (Arrow) e.getEntity();
 
if(!(arrow instanceof Arrow)) return;

Why do you check if it's an instance after you have parsed it? Wouldn't this throw a ParseException if the projectile was a fireball or snowball?

 

I dont know i was just quick coding wasnt thinking. Was wanting to check if it was possible first.

 

LucasEmanuel

No, because there is no parsing there. That is a ClassCastException

 

Hahaha oops, of course it is, silly me.